2. Sum of cube of natural numbers up to 'p' terms

1 + 2 + 3 + ... + p

\(=\) 561, then determine

1^{3} + 2^{3} + 3^{3} + ... + p^{3}

1^{3} + 2^{3} + 3^{3} + ... + p^{3}

\(=\) .

Did you find an error?