Answer in short:
In a certain breed of rabbits, the trait for long fur is dominant and the trait for short fur is recessive. A pure long-fur rabbit is crossed with a pure short-fur rabbit. Using the symbols LL for long fur and ll for short fur, determine the genotype and phenotype ratios of the Fâ generation by selfing the Fâ offspring. Draw a suitable Punnett square.
Note: Consider Dominant trait (Father) as LL & Recessive trait (Mother) as ll.
Note: Consider Dominant trait (Father) as LL & Recessive trait (Mother) as ll.
By crossing the parent gametes L & l, the F1 offspring is and it will possess as it is dominant. F2 crossing is done by selfing F1 which is Ll crossed with the same. And the punnett square is given below,
| L | l | |
| L | LL | Ll |
| l | Ll | ll |
Phenotype ratio in F2: