Solve the given problem:
Consider the binding energy of \(_{3}Li^{7}\) and \(_{2}He^{4}\) are 39.03 \(MeV\) and 29.79 \(MeV\), respectively. Which one of these two nuclei will be more stable?
Answer:
Binding energy per nucleon for lithium is \(MeV\)
Binding per nucleon for helium is \(MeV\)
nuclei will be more stable than .
[Note: Enter your answer with three decimals digits]