Give the correct answer to the following question:
The electronegativity values of some elements are \(F\) = \(4.0\), \(Cl\) = \(3.0\), \(Br\) = \(2.8\), \(I\) = \(2.5\), \(H\) = \(2.1\), and \(Na\) = \(1\). If the difference in electronegativity between two elements is \(1.7\), the bond has \(50\)% ionic character and \(50\)% covalent character; if the difference is less than \(1.7\), the bond is considered covalent, and if the difference is greater than \(1.7\), the bond is considered ionic.
The bond between hydrogen and fluorine in \(HF\) is: