Solve the given problem:
A container whose capacity is 60 \(ml\) is filled with a liquid up to 55 \(ml\). Then, the liquid in the container is heated. Initially, the level of the liquid falls from 55 \(ml\) to 48 \(ml\). Then we heat more, the level of the liquid rises to 51.2 \(ml\). Find the apparent and real expansion.
From the given data,
Level of the liquid (\(L1\)) \(=\) 55 \(ml\)
Level of the liquid (\(L2\)) \(=\) 48 \(ml\)
Level of the liquid (\(L3\)) \(=\) 51.2 \(ml\)
The formula to calculate Apparent expansion and Real expansion,
Apparent expansion \(=\)
Real expansion \(=\)
Substitute the values of \(L1\), \(L2\) and \(L3\) in above formulas,
Apparent Expansion: \(ml\)
Real Expansion: \(ml\)