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Science TNSB Mentoring
Class 10
Types of chemical reactions
Chemistry of reaction rates, pH and pOH
5.
pH calculation
Question:
6
m.
Calculate the \(pH\) of \(0.01\) \(M\) \(HNO_3\).
\([H^+] = 0.01\)
\(pH=-log_{10}[H^+]\)
\(pH=-log_{10}[OH^-]\)
\(pH=log_{10}[H^+]\)
\(pH = -log_{10}\) \([0.01]\)
\(pH = -log_{10}\) \([1\times10^{-3}]\)
\(pH = -log_{10}\) \([1\times10^{-2}]\)
\(pH = -log_{10}\) \([1\times10^{-1}]\)
\(pH = -(log_{10}1 - 1\, log_{10}10)\)
\(pH = -(log_{10}1 - 3\, log_{10}10)\)
\(pH = -(log_{10}1 - 2\, log_{10}10)\)
\(pH = 2 + 2\times\,log_{10}\,10\)
\(pH = 0 + 2\times\,log_{10}\,10\)
\(pH = 1 + 2\times\,log_{10}\,10\)
\(pH = 2 + 2\times1 = 4\)
\(pH = 0 + 2\times1 = 2\)
\(pH = 1 + 2\times1 = 3\)
Hence,
\(pH = 2\)
\(pH = 3\)
\(pH = 4\)
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