Orbital velocity — task. Science TNSB Mentoring, Class 9.

At an orbital height of 500 \(km\), find the orbital period of the satellite.

Given:

\(h\) \(=\) 500 \(km\)

\(R\) \(=\) \(6371\ km\)

\(v\) \(=\) \(7.616 kms^{-1}\)

Formula:

T = \frac{i π (i + i)}{\sqrt{\frac{i i}{(i + i)}}}

On substituting the given values, we get

T = i \times \frac{22}{7} \times \frac{(i + i)}{i}

The orbital period of the satellite is \(minutes\).

Did you find an error?

12. Orbital velocity