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Chemistry CBSE Live product
Class 10 (2026-27)
Chemical reactions and equations
Redox reaction, corrosion and rancidity
7.
Oxidation and reduction reaction
Question:
4
m.
Answer the following question:
Analyse the given equation:
\(MnO_2 + 4HCl → MnCl_2 + 2H_2O + Cl_2\)
Identify the substances which is oxidised and reduced, provide the reason for your answer.
The substance oxidised is
\(MnO_2\)
\(MnO_2\)
\(MnCl_2\)
\(HCl\)
Reason:
Hydrogen in HCl loses electrons to form H+ ions.
Chloride ions lose electrons to form chlorine gas
Chloride ions gain electrons to form chlorine gas
Hydrogen in HCl gains electrons to form H2 gas.
The substance reduced is
\(H_2O\)
\(MnO_2\)
(MnCl_2\)
\(HCl\)
Reason:
Manganese in MnO2 loses electrons to form Mn2+ in MnCl2
Manganese in MnO2 gains electrons to form Mn2+ in MnCl2
Oxygen in MnO2 loses electrons to form O2-
Oxygen in MnO2 gains electrons to form O2-
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