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Chemistry CBSE Live product
Class 10 (2026-27)
Chemical reactions and equations
Redox reaction, corrosion and rancidity
7.
Oxidation and reduction reaction
Question:
4
m.
Go through the following question and provide the answer:
Analyse the given equation:
\(CuO + H_2 → Cu + H_2O\)
Identify the oxidising and reducing agents and provide the reason for your answer.
The oxidising agent is
\(Cu\)
\(H_2\)
\(H_2O\)
\(CuO\)
Reason:
H2 loses electrons and is oxidised to H2O
Cu is already in 0 oxidation state
Cu in CuO gains electrons and is reduced to Cu
H2O is released as a liquid
The reducing agent is
\(H_2\)
\(H_2O\)
(Cu\)
\(CuO\)
Reason:
\(H_2\) loses electrons and is oxidised to \(H_2O\)
Cu is already in 0 oxidation state
H2O is released as a liquid
Cu in CuO gains electrons
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