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Chemistry CBSE Live product
Class 10 (2025-26)
Chemical reaction and equations
Annual Revision V - Chemical reactions and equations
10.
Oxidation and reduction reaction
Question:
4
m.
Read the following question and answer:
Analyse the given equation:
\(MnO_2 + 4HCl → MnCl_2 + 2H_2O + Cl_2\)
Identify the substances which is oxidised and reduced, provide the reason for your answer.
The substance oxidised is
\(MnO_2\)
\(HCl\)
\(MnO_2\)
\(MnCl_2\)
Reason:
Hydrogen in HCl gains electrons to form H2 gas.
Chloride ions gain electrons to form chlorine gas
Chloride ions lose electrons to form chlorine gas
Hydrogen in HCl loses electrons to form H+ ions.
The substance reduced is
\(MnO_2\)
\(HCl\)
(MnCl_2\)
\(H_2O\)
Reason:
Oxygen in MnO2 loses electrons to form O2-
Manganese in MnO2 loses electrons to form Mn2+ in MnCl2
Manganese in MnO2 gains electrons to form Mn2+ in MnCl2
Oxygen in MnO2 gains electrons to form O2-
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