Product of difference and sum (common fractions) — task. Maths CBSE Homework Assignments, Class 7.

Do the multiplication

(\frac{1}{6} c - \frac{2}{5} d) \cdot (\frac{1}{6} c + \frac{2}{5} d)

Choose the correct answer:

$\frac{1}{36} c^{2} + \frac{4}{30} c d + \frac{4}{25} d^{2}$
$\frac{1}{36} c^{2} - 2 \cdot \frac{1}{6} c \cdot \frac{2}{5} d + \frac{4}{25} d^{2}$
$\frac{1}{36} c^{2} - \frac{4}{30} c d + \frac{4}{25} d^{2}$
$\frac{1}{36} c^{2} + 2 \cdot \frac{1}{6} c \cdot \frac{2}{5} d + \frac{4}{25} d^{2}$
$\frac{1}{36} c^{2} - \frac{4}{25} d^{2}$

Did you find an error?

2. Product of difference and sum (common fractions)