Product of difference and sum (common fractions) — task. Maths CBSE Homework Assignments, Class 7.

Do the multiplication

(\frac{1}{6} a - \frac{3}{5} b) \cdot (\frac{1}{6} a + \frac{3}{5} b)

Choose the correct answer:

$\frac{1}{36} a^{2} - \frac{9}{25} b^{2}$
$\frac{1}{36} a^{2} + 2 \cdot \frac{1}{6} a \cdot \frac{3}{5} b + \frac{9}{25} b^{2}$
$\frac{1}{36} a^{2} - \frac{6}{30} a b + \frac{9}{25} b^{2}$
$\frac{1}{36} a^{2} - 2 \cdot \frac{1}{6} a \cdot \frac{3}{5} b + \frac{9}{25} b^{2}$
$\frac{1}{36} a^{2} + \frac{6}{30} a b + \frac{9}{25} b^{2}$

Did you find an error?

2. Product of difference and sum (common fractions)