Given that \(\sin\)  α \(+ \cos\ \) α \( = p\), verify that \(sin^4\ \) α \(+ \cos^4\ \) α\( =\) \(\frac{2 - (p^2 - 1)^2}{2}\).
 
Proof
 
Given \(\sin\ \)α \(+ \cos\ \) α\(= p\)
 
Squaring on both sides. 
 
\((\sin\ \)α \(+ \cos\ \) α\()^2 = p^2\)
 
\(\sin^2\ \)α \(+ \cos^2\ \)α \(+ 2\sin\ \)α \(\cos\ \)α \(= p^2\)
 
sinαcosα=piii
 
sin2αcos2α=piiii
 
sin4α+cos4α=siniα+iiαi2iiαiiα
 
=i2pii2i
 
=ipii2i
 
=ipii2i
 
Hence proved.