If \(\alpha\) and \(\beta\) are the zeros of the quadratic polynomial \(f(x)=x^2-\)\(t\)\((x+1)-\)\(d\), prove that \((\alpha+1)(\beta+1)=1-\)\(d\)
Proof:
\(\alpha +\beta=\)
\(\alpha \beta=\)
\((\alpha +1)(\beta +1)=\)
Answer variants:
\(1 + \)\(d\)
\(-\)\(t\)\(-\)\(d\)
\(t\)
\(1 - \)\(d\)
\(t\)\(-\)\(d\)
\(-\)\(t\)
\(d\)