Let us consider the trapezium \(ABCD\) given below:
Here, \(AB\) \(=\) 18 \(cm\), \(AD\) \(=\) \(BC\) \(=\) 7 \(cm\) and \(CD\) \(=\) 32 \(cm\). Also, \(AB \parallel CD\) and they are 6 \(cm\) apart.
\(4\) arcs are cut with 1.5 \(cm\) as radius with \(A\), \(B\), \(C\) and \(D\) as centre respectively. [Use \(\pi\) \(=\) \(\frac{22}{7}\)]
Area of trapezium \(=\) \(cm^2\).
Cumulative area of sector \(=\) \(cm^2\).
The cumulative area of the shaded regions \(=\) \(cm^2\).
Answer variants:
7.07
142.93
150
10.5
50