Assertion (A): Sum of \(n\) terms of an \(A.P.\) \(5,1,-3,-7,-11,..\) is \(-\frac{n}{2}[4n-14]\)
 
Reason (R): The sum of \(n\) terms of an \(A.P.\) is given by \(S_n=\frac{n}{2}[2a+(n-1)d]\)