TBQ - Check if the given statement is true — task. Maths CBSE Live product, Class 10 (2026-27).

Points \(A(-6,10)\), \(B(-4,6)\) and \(C(9,-20)\) are collinear such that \(AB=\frac{2}{15} AC\).

Answer:

\(AB\) \(=\)

i \sqrt{i}

\(BC\) \(=\)

i \sqrt{i}

\(CA\) \(=\)

i \sqrt{i}

Here, \(AB + BC\) \(CA\).

Thus, the points are .

\begin{array}{l} AC = 15 \sqrt{5} \times (\frac{i}{i}) \\ AC = \frac{i}{2} \times i \sqrt{i} \end{array}

\(\Rightarrow\) \(AB=\frac{2}{15} AC\)

Therefore, the given statement is .

Did you find an error?

7. TBQ - Check if the given statement is true