Find the vertices of a triangle \(ABC\) with \(A (3, -2)\), and the midpoints of sides through \(A\) being \( (2  , -5)\) and \((0, -1)\).
 
Answer:  
 
The coordinate of the point \(B\) is \((\),\()\)
 
The coordinate of the point \(C\) is \((\),\()\)