Points \(A(-6,10)\), \(B(-4,6)\) and \(C(5,-12)\) are collinear such that \(AB=\frac{2}{11} AC\).
 
Answer:
 
\(AB\) \(=\) ii
 
\(BC\) \(=\) ii
 
\(CA\) \(=\) ii
 
Here, \(AB + BC\) \(CA\).
 
Thus, the points are .
 
AC=115×iiAC=i2×ii
 
\(\Rightarrow\) \(AB=\frac{2}{11} AC\)
 
Therefore, the given statement is .