Points \(A(-6,10)\), \(B(-4,6)\) and \(C(5,-12)\) are collinear such that \(AB=\frac{2}{11} AC\).
Answer:
\(AB\) \(=\)
\(BC\) \(=\)
\(CA\) \(=\)
Here, \(AB + BC\) \(CA\).
Thus, the points are .
\(\Rightarrow\) \(AB=\frac{2}{11} AC\)
Therefore, the given statement is .