Triangle \(ABC\) with vertices \(A (–6, 0)\), \(B (6, 0)\) and \(C (0,6)\) is similar to triangle \(DEF\) with vertices \(D (–12, 0)\), \(E (12, 0)\) and \(F (0,12)\).
 
Answer:
 
Length of \(AB\) \(=\) i
 
Length of \(BC\) \(=\) ii
 
Length of \(CA\) \(=\) ii
 
Length of \(DE\) \(=\) i
 
Length of \(EF\) \(=\) ii
 
Length of \(FD\) \(=\) ii
 
\(\frac{AB}{DE} = \frac{BC}{EF} = \frac{CA}{FD} =\) ii
 
Thus, the ratio of the corresponding sides of a two triangle are .
 
Hence, triangle \(ABC\) is  to triangle \(DEF\).
 
Therefore, the given statement is .