If \(C\sin^3 A + D\cos^3 A= \sin A \cos A \) and \(C\sin A = D\cos A\), then compute the value of \(C^2 +D ^2\)
 
Proof: 

Given:  
We have, \(C\sin^3  A+ D\cos^3 A = \sin A \ cos A\) - - - (i)

and \(C\sin A = D\cos A\) - - - (ii)

Ci3A+CiAcos2A=sinAcosA

CiAsin2A+iiA=sinAcosA

CiA=sinAcosA

C=iA - - - \((iii)\)

Now, substituting \(C\) in \((ii)\)
 
iAsinA=DcosA

This implies that D=iA - - - (iv)

From (iii) and (iv),

C2+D2=i