Given that \(\sin\)  β \(+ \cos\ \) β \( = y\), verify that \(sin^4\ \) β \(+ \cos^4\ \) β\( =\) \(\frac{2 - (y^2 - 1)^2}{2}\).
 
Proof
 
Given \(\sin\ \)β \(+ \cos\ \) β\(= y\)
 
Squaring on both sides. 
 
\((\sin\ \)β \(+ \cos\ \) β\()^2 = y^2\)
 
\(\sin^2\ \)β \(+ \cos^2\ \)β \(+ 2\sin\ \)β \(\cos\ \)β \(= y^2\)
 
sinβcosβ=yiii
 
sin2βcos2β=yiiii
 
By using identity \(a^4+b^4 = (a^2+b^2)^2-2a^2b^2\)
 
\(sin^4 \)β\(+cos^4 \)β=iyii2i
 
Hence proved.