If \(\alpha\) and \(\beta\) are the zeros of the quadratic polynomial \(f(x)=x^2-\)\(c\)\((x+1)-\)\(s\), verify that \((\alpha+1)(\beta+1)=1-\)\(s\)
Proof:
\(\alpha +\beta=\)
\(\alpha \beta=\)
\((\alpha +1)(\beta +1)=\)
Answer variants:
\(-\)\(c\)\(-\)\(s\)
\(-\)\(c\)
\(1 - \)\(s\)
\(s\)
\(c\)\(-\)\(s\)
\(1 + \)\(s\)
\(c\)