Find a quadratic polynomial, the sum and product of whose zeroes are \(\frac{-14}{3}\) and \(\frac{8}{3}\), respectively. Also, obtain its zeroes of the polynomial by factorisation.
Answer:
Quadratic polynomial \(=\)
The zeroes are and .
Answer variants:
\(x^2 + \frac{14}{3}x + \frac{8}{3}\)
\(x = - \frac{2}{3}\)
\(x = -4\)
\(x = 4\)
\(x^2 - \frac{14}{3}x + \frac{8}{3}\)
\(x = - \frac{3}{2}\)