Find the value — task. Maths CBSE Live product, Class 10 (2026-27).

Evaluate the value of \(y\):

\(\frac{4y}{y-3}+\frac{1}{2y+3}+\frac{3y+9}{(y-3)(2y+3)}=0\)

\(y=\)

\frac{i}{i}

and

\frac{i}{i}

(Note: Enter the answer in its simplest form)

Did you find an error?

4. Find the value