In the given figure, \(OA \cdot OB = OC \cdot OD\). Show that \(\angle A = \angle C\) and \(\angle B = \angle D\).

Proof:
Given: \(OA \cdot OB = OC \cdot OD\)
\(\frac{OA}{OC}\ =\) \( \rightarrow (1) \)
Also \( \angle AOD\ =\) (Vertically opposite angles are equal) \( \rightarrow (2) \)
From (\(1) \) and \( (2)\) ,
\( \triangle AOD \sim \) [ similarity criterion ]
We know that "Corresponding angles of similar triangles are equal".
So, \(\angle A\ =\) and \(\angle D\ =\).