In triangle \(PQR\), let \(S\) and \(T\) be points on sides \(PR\) and \(QR\) respectively such that \(∠P = ∠RTS\). Establish that triangles \(RPQ\) and \(RTS\) are similar.
Proof:
In \(\Delta PQR\), points \(S\) and \(T\) on sides \(PR\) and \(QR\) such that \(\angle P = \angle RTS\).
In \(\Delta RPQ\) and \(\Delta RTS\),
\(\angle P = \angle\) (Given)
\(\angle PRQ = \angle\) ()
So, \(\Delta RPQ \sim \Delta RTS\) ()
Hence proved.