Prove the given condition — task. Maths CBSE Live product, Class 10 (2026-27).

In the given figure, \(DE || AC\) and \(DC || AP\). Prove that \(\frac{BE}{EC} = \frac{BC}{CP}\).

Answer:

In \(\Delta BPA\), we have

DC ∥ i

By theorem:

\frac{BC}{i} = \frac{i}{DA}

- - - - - - (I)

In \(\Delta BCA\), we have

DE ∥ i

By theorem:

\frac{BE}{i} = \frac{i}{DA}

- - - - - - (II)

From (I) and (II), we get:

\frac{BE}{i} = \frac{i}{i}

Hence it is proved.

Did you find an error?

4. Prove the given condition