a_16.png
 
Given that \(DE\) is parallel to \(AC\) and \(DC\) is parallel to \(AP\). Verify thatBEEC=BCCP.
Answer:
 
In \(\Delta BPA\), we have DCi.
 
By  theorem:
 
BCi=iDA - - - - - - (I)
 
In \(\Delta BCA\), we have DEi.
 
By  theorem:
 
BEi=iDA - - - - - - (II)
 
From (I) and (II), we get:
 
BEi=ii
 
Hence it is proved.