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Maths CBSE Live product
Class 10 (2026-27)
Triangles
Similarity of Triangles - BPT Theorem
6.
Verify the following
Question:
3
m.
Given that \(DE\) is parallel to \(AC\) and \(DC\) is parallel to \(AP\). Verify that
BE
EC
=
BC
CP
.
Answer
:
In \(\Delta BPA\), we have
DC
∥
i
.
By
Angle bisector
Pythagoras theorem
Basic proportionality
Converse of Basic proportionality
theorem:
BC
i
=
i
DA
- - - - - - (I)
In \(\Delta BCA\), we have
DE
∥
i
.
By
Angle bisector
Pythagoras theorem
Basic proportionality
Converse of Basic proportionality
theorem:
BE
i
=
i
DA
- - - - - - (II)
From (I) and (II), we get:
BE
i
=
i
i
Hence it is proved.
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