Find the exterior angle \(∠BCD\), if \(∠A = 50°\), and \(∠B = 60°\) geometrically.
Do you see any relation between the exterior angle and these two angles?
Construction:
Step - 1: Draw a base \(AB\).
Step - 2: Through \(A\) and \(B\) constuct angles and respectively, by drawing the other arms of the angle.
Step - 3: The of the two arms is the third vertex \(C\).
Interpretation:
The value of the exterior angle \(BCD\) is \(^{\circ}\).
Do you see any relation between the exterior angle and these two angles?
And, what is it?