Show that 810 is not a perfect square.
Let us find the factorisation of 810.
Group the factors in pairs of two numbers
Then, 810 \(=\)
Here, left over while grouping.
So, 810 is perfect square.
Then, 810 \(=\)
Here, left over while grouping.
So, 810 is perfect square.
Answer variants:
\(2\) and \(5\)
\((3 \times 3) \times (3 \times 3) \times 2 \times 5\)
\( 2 \times 3 \times 3 \times 3 \times 3 \times 5\)
not a