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Maths CBSE Live product
Class 8 (2026-27)
Power play
PT1 Revision III - Power play
1.
TBQ - Scientific notation I
Question:
2
m.
Convert them into scientific notation:
(i)
The distance between the Sun and Saturn is approximately equal to \(14,22,50,00,00,000 m =\)
\(1.4225 \times 10^{12} m\)
\(1422.5 \times 10^{12} m\)
\(0.14225 \times 10^{12} m\)
\(14.225 \times 10^{12} m\)
(ii)
The distance between the Sun and Earth is approximately equal to \(1,46,80,00,00,000 m =\)
\(146.8 \times 10^{11} m\)
\(1.468 \times 10^{11} m\)
\(0.1468 \times 10^{11} m\)
\(14.68 \times 10^{11} m\)
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