Finding the unknowns — task. Maths CBSE Live product, Class 8 (2026-27).

Determine the value of \(d\), \(e\) and \(f\) if

{(\frac{3}{4})}^{-2 d} \div {(\frac{4}{3})}^{d} = {(\frac{9}{16})}^{3}

, \(e\) \(= 2\)\(d\) \(+3\), \(f\)\(=6\)\(e\)

Answer:

\(d\) \(=\)

\(e\) \(=\)

\(f\) \(=\)

Did you find an error?

9. Finding the unknowns