NCERT | Square of Difference of two numbers | Intext | Pg.147 | Q3 — task. Maths CBSE Live product, Class 8 (2026-27).

Use the identity \((a-b)^2\) to find the values of \(99^2\).

Answer:

We can rewrite \(99^2\) as

{(i - 1)}^{i}

By the identity,

{(a - b)}^{2} = i^{i} - i i i + i^{i}

Thus, \(99^2\) \(=\) .

Did you find an error?

5. NCERT | Square of Difference of two numbers | Intext | Pg.147 | Q3