Prove that \((6p) × (3r) × (p + 2)\) \(=\) 18\(p^{2} r\) \(+\) 36\(pr\).
Proof:
\((6p) × (3r)\) \(=\)
\(\times\) \((p + 2)\)
The above product is expanded using .
The first term is expanded as follows:
18\(pr\)\(\times\) \(p\) \(=\) 18\(p^{1+1} r\) [By ]
\(=\) 18\(p^{2} r\)
The second term is expanded as follows:
18\(pr\)\(\times\) \(2\) \(=\) 18 \(\times 2\) \(p \times r\)
\(=\) \(pr\)
Combine the terms.
\((6p) × (3r) × (p + 2)\) \(=\) 18\(p^{2} r\) \(+\) \(pr\).
Hence, proved.