The area of a square of sidelength \(40\) units is \(1600\) sq. units \((40^2)\) and that of a square of sidelength \(2\) units is \(4\) sq. units \((2^2)\). Can we use this to find the area of a square of sidelength \(42\) units?
 
Answer:
 
Represent the area of the new square as the square of sum of two given units:
 
i+ii
 
To find the area of the square of sidelength \(42\) units  geometrically, we need to split the square into regions.
 
Area of a square of sidelength \(40\) units is sq. units.
 
Area of a square of sidelength \(2\) units is  sq. units
 
Area of the rectangular region is sq. units
 
The area of a square of sidelength \(42\) units \(=\) sq.units.