\(A, B\), and \(C\) are three points on a circle with centre \(O\). And, \(D\) is a point on the circle other than the arc \(ABC\) such that \(∠ADC = 52^°\). If the diameter \(BD\) bisects \(\angle AOC\), the what is the measure of \(∠BOC\) and \(∠AOB\).
Answer:
\(∠AOB=\) \(^{\circ}\)
\(∠BOC =\) \(^{\circ}\)
Are the angles \(∠ADC\), \(∠BOC\) and \(∠AOB\) are equal?