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Maths CBSE Live product
Class 9 (2026-27)
I’m Up and Down, and Round and Round
Construction of the Circle
3.
TBQ - Constuct the circumcircle
Question:
3
m.
Draw \(ΔABC\) with \(AB = 5 \ cm\), \(∠A = 70°\) and \(∠B = 60°\). Draw the circumcircle of \(ΔABC\). Is the centre inside or outside the triangle?
Construction:
Step -1:
Draw a base line segment \(AB = 5 \ cm\).
Draw a vertical line segment \(AB = 5 \ cm\).
Draw a slanting line segment \(AB = 5 \ cm\).
Step -2:
Using protractor, with \(A\) as centre, mark \(∠A = 70°\).
Using protractor, with \(B\) as centre, mark \(∠B = 70°\).
Using compass, with \(A\) as centre, mark \(∠A = 70°\).
Step - 3:
With \(B\) as centre, mark \(∠B = 60°\), such that it intersects the previous arm at \(O\) forming the triangle \(ABC\).
With \(B\) as centre, mark \(∠B = 60°\), such that it intersects the previous arm at \(C\) forming the triangle \(ABC\).
With \(A\) as centre, mark \(∠A = 60°\), such that it intersects the previous arm at \(C\) forming the triangle \(ABC\).
Step - 4:
Draw the perpendicular bisectors of the line segment \(AC\) and \(AB\)
Draw the perpendicular bisectors of the line segment \(AC\) and \(BC\)
Draw the perpendicular bisectors of the line segment \(AB\) and \(BC\)
Step - 5:
Mark the intersecting point of the perpendicular bisectors and the line segment as \(O\). Therefore,\(O\) is the circumcentre.
Mark the intersecting point of the perpendicular bisectors as \(O\). Therefore,\(O\) is the circumcentre.
Mark the intersecting point of the perpendicular bisectors as \(O\). Therefore,\(O\) is the centroid.
Step - 6:
With \(OC\) as radius and \(O\) as centre, draw the circumcircle of the triangle \(ABC\).
With \(5 \ cm\) as radius and \(O\) as centre, draw the circumcircle of the triangle \(ABC\).
With \(AB\) as radius and \(O\) as centre, draw the circumcircle of the triangle \(ABC\).
Thus,
the centre lies inside the triangle
the centre lies outside the triangle
.
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