Draw \(ΔPQR\) right angled at \(P\) with \(PQ = 4.5 \ cm\) and \(PR = 6 \ cm\). Draw the circumcircle of \(ΔABC\) and measure its circumradius?
Geometry:
Answer variants:
Using a protractor, with \(P\) as centre, mark \(\angle P = 90^{\circ}\).
Draw the perpendicular bisectors of the line segment \(PQ\) and \(QR\). And, mark their point of intersection as \(S\). Thus, \(S\) is the circumcentre.
With \(SR\) as radius and \(S\) as centre, draw the circumcircle of \(\Delta PQR\).
Draw a base line segment \(PQ = 4.5 \ cm\)
Using a compass, with \(P\) as centre, draw an arc of radius \(6 \ cm\), such that it intersects the previous arm at \(R\).
Join \(QR\) to form the triangle \(ABC\)
Construction:
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Step - 6:
Thus, the measure of circumradius is \(cm\).