In a circle, chords \(CD\) and \(YZ\) form isosceles triangles \(OCD\) and \(OYZ\) with the centre \(O\). If \(CD = YZ\), show that \(△OCD ≅ △OYZ\).
Explanation:
Proof:
In \(△COD\) and \(△YOZ\)
\(CO =\) []
\(DO =\) []
\( CD=\) []
Therefore, \(△COD ⩭ △YOZ\) ()
Answer variants:
\(YZ\)
CZ
\(YO\)
\(ZO\)