A chord of a circle of radius \(5 \ cm\) subtends \(120^{\circ}\) at the centre. Find the area of the corresponding: (i) minor sector (that subtends \(120^{\circ}\) at the centre), and (ii) major sector (that subtends \(240^{\circ}\) at the centre). (Use \(\pi \approx 3.14\))
Answer:
Area of minor sector \(=\) \(cm^2\)
Area of major sector \(=\) \(cm^2\)