Find the \(10^{\text{th}}\) and \(n^{\text{th}}\) terms of the \(G.P\): \(2, 6, 18, \ldots\)
\(10^{\text{th}}\) term is
\(n^{\text{th}}\) term is
Answer variants:
\(t_n=3\left(2\right)^{n}\)
39386
39366
\(t_n=3\left(2\right)^{n-1}\)
\(t_n=2\left(3\right)^{n-1}\)
39356
39376
\(t_n=2\left(3\right)^{n+1}\)