Prove that the following rational numbers are equal:
 
(i) \(-\frac{2}{7}\) and \(-\frac{16}{56}\) 
 
(ii) \(\frac{56}{7}\) and \(8\)
 
Solution:
 
Any two rational numbers \(\frac{a}{b}\) and \(\frac{c}{d}\) are said to be equal if i×i=i×i.
 
[Note: Enter the answer in alphabetical order.]
 
Proof:
 
(i) \(-\frac{2}{7}\) and \(-\frac{16}{56}\)
 
\(-2 \times 56\) \(=\) ......(1)
 
\(7 \times (-16)\) \(=\) ......(2)
 
Equation (1) Equation (2)
 
Therefore, \(-\frac{2}{7}\) and \(-\frac{16}{56}\) are .
 
 
(ii) \(\frac{56}{7}\) and \(8\)
 
Proof:
 
\(\frac{56}{7}\) \(=\) \(\frac{8}{1}\)
 
\(56 \times 1\) \(=\) ......(1)
 
\(7 \times 8\) \(=\) ......(2)
 
Equation (1) Equation (2)
 
Therefore, \(\frac{56}{7}\) and \(8\) are .