A rational number in its lowest form has denominator 26×53. How many decimal places will its decimal expansion have? Explain your answer.
 
Explanation:
 
Let the rational number be p26×53.
 
The decimal expansion of a rational number \(\frac{p}{q}\), where \(q≠0\) in its lowest form will be terminating when the prime factors of \(q\) are (is) .
 
Thus, the highest power of in the determines the number of decimal places.
 
First, we need to make the powers of \(2\) and \(5\) .
 
So, multiply the numerator and the denominator of the considered rational number by ii.
 
Thus, we get 125pii.
 
Therefore, the number of decimal places in the decimal expansion of the considered rational number is .