In the following figure, if \(AC = BD\), then prove that \(AB = CD\).
Proof:
From the figure, it can be observed that \(AC = \)
\(BD = \)
It is given that \(AC = BD\)
\(AB + BC = BC + CD\)---- (1)
According to Euclid’s axiom, .
Subtracting \(BC\) from equation (1) and simplifying then we get,
\(AB = CD\)