Exemplar - Prove the given — task. Maths CBSE Live product, Class 9.

In the Image , \(∠ L> ∠M\), \(KB\) is the bisector of \(∠LKM\) and \(KA⊥ LM\). Demonstrate that \(∠BKA=\frac{1}{2}(∠L−∠M)\).

\(∠LKB=∠BKM\) (\(KB\))

In \(△KLA\),

\(∠L=\)\(^°−∠LKA\) --------(2)

Again, in \(△KAM \),

\(∠M\)=\(^°−∠MKA\) -------.(3)

\(∠L−∠M=\) \(∠BKA\)

Did you find an error?

8. Exemplar - Prove the given