TBQ - Find the value — task. Maths CBSE Live product, Class 9 (2025-26).

1. If \(81x^2-b=(9x+\frac{1}{4})(9x-\frac{1}{4})\), then the value of \(b\) is

\(\frac{1}{23}\)
\(\frac{1}{15}\)
\(0\)
$\frac{1}{16}$

2. If \(a + b + c =0\), then \(a^3+b^3 +c^3\) is equal to

\(3abc\)
\(2abc\)
\(0\)
\(abc\)

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