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In a quadrilateral \(EFGH\), the diagonals \(EG\) and \(FH\) intersect each other at \(Z\) such that \(ZE:ZG\) \(= \)3:2. Is \(EFGH\) a parallelogram? Why or why not?
 
Answer:
 
Here, \(ZE:ZG\) \(= \)3:2
 
Hence,  \(ZE\) \(ZG\).
 
\(EFGH\) is parallelogram.