Answer variants:
3×1sinA13×1sinA+1
3×1cosA13×1cosA+1
3sinAcosAcosA3sinAcosA+cosA
3cosAsinAcosA3cosAsinA+cosA
3sinA13sinA+1
cosA3sinA1cosA3sinA+1
Prove that 3cotAcosA3cotA+cosA \(=\) 3cosecA13cosecA+1.
 
Proof:
 
LHS \(=\) 3cotAcosA3cotA+cosA
 
\(=\)
 
\(=\)
 
\(=\)
 
\(=\)
 
\(=\) 3cosecA13cosecA+1 \(=\) RHS