Verify the given trigonometric equation — task. Maths CBSE Mentoring, Class 10 Mentoring product.

Answer variants:

\sqrt{\frac{{(1 + \sin β)}^{2}}{1 + \sin^{2} β}}

\sqrt{\frac{1 + \sin β}{1 - \sin β} \times \frac{1 + \sin β}{1 + \sin β}}

\sqrt{\frac{1 + \sin β}{1 - \sin β} \times \frac{1 - \sin β}{1 - \sin β}}

\frac{1 + \sin β}{\cos β}

\frac{1}{\cos β} + \frac{\sin β}{\cos β}

\sqrt{\frac{{(1 + \sin β)}^{2}}{1 - \sin^{2} β}}

\sqrt{\frac{{(1 + \sin β)}^{2}}{\cos^{2} β}}

Verify that

\sqrt{\frac{1 + \sin β}{1 - \sin β}}

\(=\)

\sec β + \tan β

Proof:

LHS \(=\)

\sqrt{\frac{1 + \sin β}{1 - \sin β}}

\(=\)

\sec β + \tan β

\(=\) RHS

Did you find an error?

2. Verify the given trigonometric equation