TBQ - Find the value — task. Maths CBSE Mentoring, Class 9 Mentoring product.

If \(a=6+2\sqrt{3}\) and \(b=\frac{1}{a}\), then estimate the value of \(a^2+b^2\).

\(a^2+b^2=\)

$\frac{{(150 + 46 \sqrt{3})}^{2} + 1152}{576}$
$\frac{{(150 + 46 \sqrt{3})}^{2} - 2}{576}$
$\frac{{(150 + 46 \sqrt{3})}^{2} + 2}{576}$
$\frac{{(150 + 46 \sqrt{3})}^{2} - 1152}{576}$

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