If \(x = \frac{a^2 + 3a - 4}{17a^2 - 17}\)  and \(y = \frac{a^2 + 2a - 8}{2a^2 - 2a - 4}\), calculate the value of \(x^2 y^{-2}\).
 
Answer:
 
The value of \(x^2 y^{-2}\) is ii.